Find the Sin A, Cos A, and Tan A. (Write your answer as simplified ratios.)

Question

asked Dec 17, 2020 210k views

1 Answer

Aniruddh Thakor · Answer 1 · 2020-12-21T05:16:26+0000

Answer:

see explanation

Explanation:

sinA =
(opposite)/(hypotenuse) =
(BC)/(AB) , thus

sinA =
(2√(19) )/(20) =
(√(19) )/(10)

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cosA =
(adjacent)/(hypotenuse) =
(AC)/(AB) , thus

cosA =
(18)/(20) =
(9)/(10)

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tanA =
(opposite)/(adjacent) =
(BC)/(AC) , thus

tanA =
(2√(19) )/(18) =
(√(19) )/(9)