Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x?

Question

asked Aug 19, 2020 99.8k views

2 Answers

Rmaruszewski · Answer 1 · 2020-08-25T06:44:08+0000

Answer:

$x_1=1.23\\x_2=-0.40$

Explanation:

Given a quadratic equation in the form
ax^2+bx+c=0 , you can use the Quadratic formula to solve it. This is:

$x=(-b\±√(b^2-4ac))/(2a)$

Then, you need to subtract
from both sides of the equation given:

$5x-5x=6x^2-3-5x\\0=6x^2-5x-3$

You can identify that:

$a=6\\b=-5\\c=-3$

Then, substituting values into the Quadratic formula, you get:

$x=(-(-5)\±√((-5)^2-4(6)(-3)))/(2(6))$

$x_1=1.23\\x_2=-0.40$