asked 82.6k views
5 votes
Determine the projection of u=1.6i+3.3j in the v=-2.1i-0.5j direction

2 Answers

3 votes

Answer:

answer is B i think on edg. 2.3i+0.5j

Explanation:

just took the test

answered
User Brentlightsey
by
8.0k points
2 votes

The projection of
\vec u onto
\vec v is


\mathrm{proj}_(\vec v)(\vec u)=(\vec u\cdot\vec v)/(\vec v\cdot\vec v)\vec v

We have


\vec u\cdot\vec v=1.6\cdot(-2.1)+3.3\cdot(-0.5)=-5.01


\vec v\cdot\vec v=\|\vec v\|^2=(-2.1)^2+(-0.5)^2=4.66


\implies\mathrm{proj}_(\vec v)(\vec u)=(-5.01)/(4.66)\vec v\approx2.26\,\vec\imath+0.54\,\vec\jmath

answered
User Dnp
by
8.8k points
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