What is the surface area of the figure shown? 484.8 square inches 500.8 square inches 452.8 square inches 404.8 square inches

Question

asked Jan 2, 2020 115k views

1 Answer

Tarulen · Answer 1 · 2020-01-07T06:39:26+0000

Answer:

The surface area is
$404.8\ in^(2)$

Explanation:

we know that

The surface area of the figure is equal to

SA=2B+PL

where

B is the area of the trapezoidal face

P is the perimeter of the trapezoidal face

L is the length of the figure

Find the area of B

$B=(1)/(2)(15+5)8\\ \\B=80\ in^(2)$

Find the perimeter P

$P=(8+5+12.8+15)=40.8\ in$

we have

$L=6\ in$

substitute the values

$SA=2(80)+(40.8)(6)=404.8\ in^(2)$