Question

Please solve for the inverse variation equation

Answer 1

f(x) =
`(1)/(x-2) + 1`

Explanation:

First we identify the Vertical Asymptote. Which is at x = 2

The function has a VA only at the point where the denominator gives 0, so because we know x = 2 is the VA, the denominator will be x - 2.

Then we identify the Horizontal Asymptote, which is the behavior of the function for very large 'x', or the horizontal line of the graph on the y - axis. Which is at y = 1. So our function will go to 1, as x grows incredibly large.

But since our denominator is x - 2, the top remains 1, but we should add a 1 to the function so it really has a HA at y = 1.

f(x) =
`(1)/(x-2) + 1`