Question

A cyclist travels at a constant velocity of 3.2m/s westward, then speeds up with a steady acceleration of 2.3m/s^2. Calculate the cyclist’s speed after accelerating for 5.0 s.

*also tell how to work out problem*

Answer 1

14.7 m/s

Step-by-step explanation:

In this problem we have

u = 3.2 m/s is the initial velocity of the cyclist

a = 2.3 m/s^2 is the acceleration of the cyclist

We want to know the cyclist speed after a time of

t = 5.0 s

So we can use the following equation:

`v=u+at`

Substituting the numbers, we find

`v=3.2 m/s + (2.3 m/s^2)(5.0 s)=14.7 m/s`