Question

What is p(t)=-log_10(t)^.5 in exponential form

Answer 1

`10^(-p\left(t\right))=t^(\left(0.5\right))`

Explanation:

Given equation is
`p\left(t\right)=-\log_(10)t^\left(0.5\right)`

Now question says to write that in exponential form.

So we can use the following conversion formula:

`\log_ca=b\ \Rightarrow c^b=a`

`p\left(t\right)=-\log_(10)t^\left(0.5\right)`

`-p\left(t\right)=\log_(10)t^\left(0.5\right)`

`\log_(10)t^\left(0.5\right)=-p\left(t\right)`

Apply conversion formula

`p\left(t\right)=-\log_(10)t^\left(0.5\right)\ \Rightarrow 10^(-p\left(t\right))=t^(\left(0.5\right))`

`10^(-p\left(t\right))=t^(\left(0.5\right))`