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Defined the end behavior of the following function f(x)=-x^5+x^2-x

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User Sparkle
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2 Answers

6 votes

Answer:

Explanation:

Note that the highest power of x is 5, which is odd. Also note that the sign of the coefficient of x^5 is negative. Hence, the graph begins in Quadrant II, generally decreasing as x increases, and ends in Quadrant IV.

answered
User Taro Kiritani
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8.7k points
2 votes

Answer: the graph of the function starts high and ends low

Explanation:

A P E X

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User Tool
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