Write an equation for the line that is parallel to the given line and that passes through the given point. y = 5/2 x – 10; (–6, –29)

Question

asked Nov 28, 2020 128k views

1 Answer

Mighty Badaboom · Answer 1 · 2020-12-04T23:45:13+0000

Answer:
y=(5)/(2)x-14

Explanation:

The equation of the line in slope-intercept form is:

y=mx+b

Where m is the slope and b the intersection with the y-axis.

You know the line
y=(5)/(2)x-10

You can identify that:

m=(5)/(2)

The slopes of Parallel lines are equal, then the slope of the other line is
m=(5)/(2)

Substitute the slope and the given point into
y=mx+b and solve for b:

$-29=(5)/(2)(-6)+b\\-29=-15+b\\-29+15=b\\b=-14$

Substituting values, you get that the equation of this line is:

y=(5)/(2)x-14