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What is an equation of the line that passes through the point (−1,8) and is parallel to the line x+y=4?

asked
User Kshama
by
8.3k points

1 Answer

4 votes

Answer:

y = -x+7

Explanation:

We need to get x+y=4 in slope intercept from to determine the slope

x+t=4

Subtract x from each side

x-xy = -x+4

y= -x+4

The slope is -1

Parallel lines have the same slope

We have the slope and a point of the new line.

We can use the point slope form

y-y1 = m(x-x1)

y-8 = -1(x--1)

y-8 = -1(x+1)

Distribute the negative sign

y-8 = -x-1

Add 8 to each side

y-8+8 = -x-1+8

y = -x+7

answered
User Igor Klimer
by
8.3k points

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