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What is the solution to the equation below? 3log4x=log432+log42 X=-8 X=-4 X=4 X=8

What is the solution to the equation below? 3log4x=log432+log42 X=-8 X=-4 X=4 X=8
asked 195k views
5 votes
What is the solution to the equation below?

3log4x=log432+log42
X=-8
X=-4
X=4
X=8

What is the solution to the equation below? 3log4x=log432+log42 X=-8 X=-4 X=4 X=8-example-1
asked
User Mossa
by
8.0k points

2 Answers

1 vote

Answer: 4

Step-by-step explanation: Its on EDG

answered
User AHM
by
7.9k points
4 votes

Answer:


\large\boxed{x=4}

Explanation:


3\log_4x=\log_432+\log_42\qquad\text{use}\ \log_ab^c=c\log_ab\ \text{and}\ \log_ab+\log_ac=\log_a(bc)\\\\\log_4x^3=\log_4(32\cdot2)\\\\\log_4x^3=\log_464\iff x^3=64\to x=\sqrt[3]{64}\\\\x=4

answered
User His
by
8.4k points
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