Answer:
 find heat released by the burn: 
(2 g) (19.4 kJ/g) = 38.8 kJ released 
 
find heat gained by the water: 
dH = m C dT 
dH = (2250 g) (4.184 J/g-C) (+ 3.17 C) 
dH = 29,842 Joules 
aka 
dH water = + 29.8 kJ 
 
find the missing heat given to the calorimeter 
(38.8 kJ released) - (29.8 kJ given to water) = 9.0 kJ given to calorimeter 
 
What is the heat capacity of the empty bomb calorimeter 
(9.0 kJ given to calorimeter) / (3.17 C rise in temp) = 2.84 kJ / C