Question

Mr. Clarke built a deck around the swimming pool and sandbox in his backyard. What is the area of the decking that surrounds the pool and sandbox, rounded to the nearest tenth of a square foot?

Answer 1

`1,174.8\ ft^(2)`

Explanation:

we know that

The area of the decking is equal to the area of the parallelogram minus the area of the pool minus the area of the sand box

Remember that

`21(1)/(2)\ ft=21.5\ ft`

so

`A=(50)(35)-(20)(25)-(21.5)(7)/2\\A= 1,750-500-75.25\\A=1,174.8\ ft^(2)`