Question

Over a span of 6.0 seconds, a car changes its speed from 89 km/h to 37 km/h. What is its average acceleration in meters per second squared (m/s2)?

Answer 1

Answer: Average acceleration is -2.407
`(m)/(s^(2))`

Step-by-step explanation:

Average acceleration is equal to change in velocity divided by time taken

therefore,
`a=(Vf-Vi)/(t)`

=>
`a=(37-89)/(6)* (5)/(18)(m)/(s^(2)) = -2.407 (m)/(s^(2))`