Question

2 Al + 3 Cl2 = 2 AlCl3

114g Al
186g Cl2
to use all of the Al how much Cl2 is required

Answer 1

1 mol Al. 26.9815 g Al. ×. 2 mol AlCl. 3. 2 mol Al. =0.100 mol AlCl3. The balanced equation says: 3 mol Cl2 produces ... that the initial mass of Al was larger than required to react with all of the Cl2. The sum of the masses.

Explanation:1 mol Al. 26.9815 g Al. ×. 2 mol AlCl. 3. 2 mol Al. =0.100 mol AlCl3. The balanced equation says: 3 mol Cl2 produces ... that the initial mass of Al was larger than required to react with all of the Cl2. The sum of the masses.

Answer 2

ur mom

Step-by-step explanation: