Question

Find the y-intercept for the parabola defined by the equation y=x^2-x-12

Answer 1

The y-intercept is (0,-12).

Explanation:

Given equation is
`y=x^2-x-12`.

Now question says to find the y-intercept of the given parabola
`y=x^2-x-12`.

We know that y-intercept means the y-value when x-value equals 0

so let's plug x=0 into given equation
`y=x^2-x-12` then solve that for y.

`y=x^2-x-12`

`y=0^2-0-12`

`y=0-0-12`

`y=-12`

Hence the y-intercept is (0,-12).