Question

Which is one of the solutions to the equation 2x^2 - x - 4 = 0

Answer 1

`x_(1)=(1+√(33) )/(4)\\x_(2)=(1-√(33) )/(4)`

Explanation:

Using quadratic formula

`x=\frac{-b+-\sqrt{b^(2)-4*a*c} }{2*a}`

we will have two solutions.

2x^2 - x - 4 = 0

So, a=2 b=-1 c=-4, we have:

`x_(1)=\frac{+1+\sqrt{-1^(2)-4*2*-4} }{2*2}\\\\x_(2)=\frac{+1-\sqrt{-1^(2)-4*2*-4} }{2*2}`

Finally, we have two solutions:

`x_(1)=(1+√(33) )/(4)\\\\x_(2)=(1-√(33) )/(4)`