Question

2. Write the equation of the circle in general form. Show all of your work.

Answer 1

The general form is;

`x^2+y^2+6x-8y+21=0`

Explanation:

The given circle has center (h,k)= (-3,4) and radius r=2 units.

The equation of the circle is found using the formula;

`(x-h)^2+(y-k)^2=r^2`

We plug in the values to get;

`(x+3)^2+(y-4)^2=2^2`

`(x+3)^2+(y-4)^2=4`

Expand;

`x^2+6x+9+y^2-8y+16=4`

`x^2+y^2+6x-8y+16+9-4=0`

The general form is;

`x^2+y^2+6x-8y+21=0`