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What volume will 1.12 moles of nitrogen gas occupy at STP

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Answer:

Step-by-step explanation:

Volume occupied by Nitrogen gas at STP = number of moles x 22.4dm³/mol

Number of moles = 1.12moles

Volume = 1.12 x 22.4

Volume at STP = 25.1dm³

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User Renzo
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