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Identify this conic section. 16y = x^2

1 Answer

5 votes

ANSWER

A parabola.

Step-by-step explanation

The given conic is :


16y = {x}^(2)

This can be rewritten as:


{x}^(2) = 16y


{x}^(2) = 4(4)y

This is a parabola with the vertex at the origin.

The foci is (0,4)

Therefore the given conic section is a parabola that has an axis of symmetry parallel to the y-axis.

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User Lizardx
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