Question

A small submarine is at –1,320 feet in relation to sea level. The submarine needs to be at 180 feet below sea level in 60 minutes. Another submarine is at –1,440 feet, and also needs to be at 180 feet below sea level in 60 minutes. How much faster does the second submarine need to travel? Explain.

Answer 1

The first submarine needs to travel at a rate of [-180 – (-1,320)] ÷ 60 = 19 feet per minute.

The second submarine needs to travel at a rate of [-180 – (-1,440)] ÷ 60 = 21 feet per minute.

21 – 19 = 2, so the second submarine must travel 2 feet per minute faster than the first sub.

Explanation:

got it right on edge please give points

Answer 2

Answer: The first submarine needs to travel at a rate of [-180 – (-1,320)] ÷ 60 = 19 feet per minute.

The second submarine needs to travel at a rate of [-180 – (-1,440)] ÷ 60 = 21 feet per minute.

21 – 19 = 2, so the second submarine must travel 2 feet per minute faster than the first sub.

Explanation:

edge2020