Question

2.0 *10^13 electrons flow through a transistor in 1.0 ms. What is the current through the transistor?

Answer 1

0.0032 A

Step-by-step explanation:

The magnitude of the charge of one electron is

`q=1.6\cdot 10^(-19) C`

Therefore, if we have a total of

`N=2.0\cdot 10^(13)` electrons, their total charge would be

`Q=Nq=(2.0\cdot 10^(13))(1.6 \cdot 10^(-19)C)=3.2\cdot 10^(-6) C`

The current in the transistor is given by

`I=(Q)/(t)`

where

Q is the total charge of the electrons flowing through it

t = 1.0 ms = 0.001 s is the time taken

Substituting into the equation, we find

`I=(3.2\cdot 10^(-6) C)/(0.001 s)=0.0032 A`