Question

A^2-2a+10=0 find the roots

Answer 1

a = 1 ± 3i

Explanation:

Rearranging, you have ...

(a^2 -2a +1) +9 = 0

(a -1)^2 = -9 . . . . . . . . subtract 9, write as a square

a -1 = ±3i . . . . . . . . . . take the square root

a = 1 ±3i . . . . . . . . . . . add 1