Answer:
The area of the white region = 16π - 16 ⇒ third answer
Explanation:
* Look at the figure and lets explain it
- A circle with two diameters perpendicular to each other
- Two shaded isosceles right angled triangle with leg length 4 units
* To find the area of the white region:
- Find the area of the circle ⇒ (1)
- Find the area of the two shaded triangles ⇒ (2)
- Subtract (2) from (1)
* Lets do that
∵ The length of the radius of the circle = 4 units
∴ The area of the circle = π (4)² = 16π
∵ The area of each triangle = (1/2) × base × height
∵ The length of the base and the length of the height = 4 units
∴ The area of the two triangles = 2 × 1/2 × 4 × 4 = 16 units
* Lets subtract the area of the triangles from the area of the circle
∴ The area of the white region = 16π - 16