Question

What is f(x)=-3(x+1)(x+1) in standard form

Answer 1

f(x) = 3x² + 6x + 3

Explanation:

The standard form of a quadratic is
`ax^2 + bx + c`. To write the equation f(x)=-3(x+1)(x+1) in standard form, multiply the factors using the distributive property and combining like terms.

f(x)=-3(x+1)(x+1)

f(x) = 3(x²+x+x+1)

f(x) = 3x² + 3x + 3x + 3

f(x) = 3x² + 6x + 3