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En un triangulo rectangulo ABC (B=90) REDUCE: J=(sec2C-cot2A) (sen2C+sen2A) es para hoy porfaaaa

En un triangulo rectangulo ABC (B=90) REDUCE: J=(sec2C-cot2A) (sen2C+sen2A) es para hoy porfaaaa
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3 votes
En un triangulo rectangulo ABC (B=90) REDUCE:

J=(sec2C-cot2A) (sen2C+sen2A) es para hoy porfaaaa

asked
User Rosenthal
by
7.8k points

1 Answer

1 vote

Answer:

puc provar, però no sé lemme see

answered
User Ususer
by
7.8k points
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