Question

Suppose a bag contains 7 blue chips and 3 gold chips. What is the probability of randomly choosing a blue chip not replacing it, and then randomly choosing another blue chip?

Answer 1

7/10 × 6/9 = 42/90 = 7/15

Explanation:

so theres 10 chips total.

on the first draw there 7 blue chips and a total of 10 chips of both colors

take one away from the 7 chips we have and get 6 over the 9 chips.

Answer 2

Answer:
`(7)/(15)`

Explanation:

Given : The number of blue chips in the bag = 7

The number of gold chips in the bag = 3

Total number of chips : 7+3=10

Now, the probability of randomly choosing a blue chip not replacing it, and then randomly choosing another blue chip is given by :-

`(6*7)/(9*10)=(7)/(15)`

Hence, the probability of randomly choosing a blue chip not replacing it, and then randomly choosing another blue chip
`=(7)/(15)`