Question

Please help! functions operations. explain please

Answer 1

Answer:


`f^(-1)(x)=\pm √(x-7)`

Explanation:

Given
`f(x)=x^2+7`

Let


`y=x^2+7`

Interchange x and y


`x=y^2+7`

Solve for y.


`x-7=y^2`

Take square root of both sides.


`y=\pm √(x-7)`

Hence the inverse of the given function is;


`f^(-1)(x)=\pm √(x-7)`

Third choice is correct.