Question

What is the angular velocity of the hour hand of a clock?

Answer 1

`1.74\cdot 10^(-3)rad/s`

Step-by-step explanation:

The angular velocity of the hour hand is given by:

`\omega=(2 \pi)/(T)`

where

`2 \pi` is the angular displacement (in radians) corresponding to one complete rotation

T is the period of the hour hand (the time it takes to complete one rotation)

The period of the hour hand is 1 hour, which is

`T=1 h=3600 s`

So the angular velocity is

`\omega=(2 \pi)/(3600 s)=1.74\cdot 10^(-3)rad/s`