Question

The equation of the circle whose center is at (3, 7) and whose radius is 6 is

(x + 3)² + (y + 7)² = 6
(x + 3)² + (y + 7)² = 36
(x - 3)² + (y - 7)² = 36

Answer 1

`\large\boxed{(x-3)^2+(y-7)^2=36}`

Explanation:

The equation of a circle:

`(x-h)^2+(y-k)^2=r^2`

(h, k) - center

r - radius

We have

(3, 7) - center

r = 6 - radius

Substitute:

`(x-3)^2+(y-7)^2=6^2\\\\(x-3)^2+(y-7)^2=36`