Question

Please help me with this! Show work if possible

Answer 1

True

Explanation:

Suppose you have a quadratic function

`ax ^ 2 + bx + c = 0`

Factoring this expression results in:

`ax ^ 2 + bx + c = (x-h) (x-k) = 0`

Where h and k are real numbers.

Then the function is equal to 0 when
`x = h` and when
`k = 0`.

Therefore h and k will always be the solutions when we have the quadratic function factored in the form

`(x-h)(x-k) = 0`

Since we have ensured that the factors of the function contain only real numbers, then h and k are real numbers, and x and y must also be real numbers. Therefore solutions to an equation in this form will always be real solutions.

The statement is true