Question

Find the slope of the line perpendicular to the line passing through (-3,0) and (4,-5)​

Answer 1

`m_(2)= (7)/(5)`

Explanation:

`m_(1)=(y_(2) -y_(1) )/(x_(2)-x_(1))\\ m_(1)=(-5-0)/(4+3)\\m_(1)=(-5)/(7)`

2 lines are perpendicular if their slopes meet the following condition:

`m_(2)*m_(1) =-1`

solving for
`m_(2)` we have:

`m_(2)*(-5)/(7) =-1\\m_(2) =(-1)/((-5)/(7))\\Finally\\m_(2) =(7)/(5)`