asked 48.9k views
2 votes
What is the y-value of the vertex 4x^2 +8x-8

asked
User IXs
by
8.0k points

1 Answer

5 votes

Answer:

-12

Explanation:

Here the coefficients a, b and c are 4, 8 and -8 respectively.

-b

A formula for the axis of symmetry is x = -------

2a

-8

... which yields x = --------- = -1

2(4)

Evaluating f(x) = 4x^2 + 8x - 8 at x = -1 yields f(-1) = 4(-1)^2 + 8(-1) - 8 = -12.

The y-value of the vertex is -12. Note that the vertex lies right smack on the axis of symmetry.

answered
User ZaxR
by
9.0k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.