What is the average rate of change for the function f(x)=3(0.25)^x over the interval -2 ≤ x ≤ 0

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asked Jun 13, 2020 117k views

1 Answer

Yucel Bayram · Answer 1 · 2020-06-20T01:04:19+0000

Answer:
-22.5

Explanation:
Use the average rate of change equation
f(b)-f(a) / b-a
f(b) = f(0) = 3(.25)^0 = 3
f(a) = f(-2) = 3(.25)^-2 = 48

(3-48)/ 0-(-2)
(-45) / 2
-22.5

What is the average rate of change for the function f(x)=3(0.25)^x over the interval -2 ≤ x ≤ 0

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