Question

What is the are of the following figure if AC = 12, AD = 16.

Answer 1

116

Explanation:

∆ABC

A = ½bh = ½ × 12 × 6 = 36

∆ACD

A = ½bh = ½ × 16 × 7 = 56

∆ADE

A = ½bh = ½ × 16 × 3 = 24

ABCDE

A = ∆ABC + ∆ACD +∆ADE = 36 + 56 + 24 = 116

The area of the figure is 116 square units.