Question

The general term of an arithmetic sequence is tn = 32 + 3n, where n ∈N and n ≥ 1. The sequence is

A) 32, 35, 38, 41, 44, 47,...
B) 32, 96, 288, 864, 2592, 7776,...
C) 34, 39, 44, 49, 54, 59,...
D) 35, 38, 41, 44, 47, 50,...

Answer 1

D) 35, 38, 41, 44, 47, 50, ...

Explanation:

tₙ = 32 + 3n; n ∈ N, n ≥ 1

t₁ = 32 + 3(1) = 32 + 3 = 35

t₂ = 32 + 3(2) = 32 + 6 = 38

t₃ = 32 + 3(3) = 32 + 9 = 41

t₄ = 32 + 3(4) = 32 + 12 = 44

t₅ = 32 + 3(5) = 32 + 15 = 47

t₆ = 32 + 3(6) = 32 + 18 = 50

The sequence starts at t₁ = 35 and each term is 3 units greater than the preceding term.

The sequence is 35, 38, 41, 44, 47, 50, ...