Question

(( REPOST ))((THIS IS MULTIPLE CHOICE BUT I NEED HELP ))

a town has a population of 32,000 in the year 2002; 35,200 in the year 2003; 38,720 in the year 2004; and 42,592 in the year 2005. if this pattern continues, what will the population be in the year 2015?

a) 110,473
b) 100,430
c) 133,672
d) 121,520

Answer 1

Not sure it's asking for 2015.

I looked similar problem saying 2016.

Answers:

if it's 2015: A

if it's 2016: D

Answer 2

117417 people

Explanation:

Let's use the equation A = Pe^rt.

A = amount

P = starting amount

r = rate

t = time

Let's find r first using years 2002 and 2003.

35200 = 32000e^r

Divide each side by 32000.

35200/32000 = e^r

Take the ln() of each side.

r = ln(35200/32000)

Now we can solve for year 2015.

A = 32000e^ln(35200/32000)*13

A = 32000e^1.2390323374562242

A = 110473