Answer:
x^4- x^3- 4x^2-3
Explanation:
Given
f(x)= x^4- x^2+9
And
g(x)= x^(3 )+ 3x^2+12
We have to find
(f-g)(x)= ?
The operations on functions are as easy as the operations on numbers or polynomials.
We have to subtract the functions to find the above mentioned operation.
=(f-g)(x)=f(x)-g(x)
(f-g)(x)=[x^4- x^2+9]-[x^(3 )+ 3x^2+12]
The minus will change the signs of function g.
= x^4- x^2+9- x^(3 )- 3x^2-12
= x^4- x^3- x^2- 3x^2+9-12
=x^4- x^3- 4x^2-3