Question

Which of following equations is of a parabola with a vertex at (3,0)? Y=(x-3)^2, y=x+3^2, y=x^2-3, y=x^2+3

Answer 1

y = (x - 3)²

Explanation:

The vertex of the general equation of the parabola of the form:

y = (x - h)² + k

is at (h, k)

We are given that the vertex is at the point (3, 0)

This means, h = 3 and k = 0

Using these values in the first equation, we get:

y = (x - 3)² + 0

y = (x - 3)²

Therefore, 1st option gives the parabola with vertex at (3, 0)