If the length of each leg of an isosceles triangle is 13 and the base is 24 the length of the altitude to the base is

Question

asked Dec 11, 2020 72.7k views

2 Answers

Prianca · Answer 1 · 2020-12-15T13:21:16+0000

Answer:

The altitude to the base is
$5\ units$

Explanation:

we know that

To find the length of the altitude apply the Pythagoras Theorem

Let

h-----> the altitude

h^(2)=13^(2)-(24/2)^(2)

h^(2)=13^(2)-(12)^(2)

h^(2)=169-144

h^(2)=25

$h=5\ units$