Question

If the equation of a circle is (x+5)^2 + (y-7)^2=36, its center point is​

Answer 1

centre = (- 5, 7 )

Explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x + 5)² + (y - 7)² = 36 ← is in standard form

with h = - 5 and k = 7

centre = (- 5, 7)