Question

Find the area of the kite. The figure is not drawn to scale.

Answer 1

The area of the kite is
`42\ units^(2)`

Explanation:

we know that

The area of a kite is half the product of the diagonals

so

`A=(1)/(2)(D1*D2)`

we have

`D1=2*(3)=6\ units`

Find the length side of diagonal D2

Applying the Pythagoras Theorem

`D2=\sqrt{5^(2)-3^(2)} +10\\ \\D2=4+10\\ \\D2=14\ units`

Find the area of the kite

we have

`D1=6\ units`

`D2=14\ units`

substitute

`A=(1)/(2)(D1*D2)`

`A=(1)/(2)(6*14)=42\ units^(2)`