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If the pressure acting on a given sample of an ideal gas at constant temperature is tripled, what happens to the volume of the gas? a)The volume is reduced to one-third of its original value. b)The volume is reduced to one-ninth of its original value. c) The volume remains constant. d)The volume is increased by a factor of three times its original value. e) The volume is increased by a factor of nine times its original value.

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User ACengiz
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Answer:

a)The volume is reduced to one-third of its original value.

Step-by-step explanation:

For a gas at constant temperature, we can apply Boyle's law, which states that the product between pressure and volume is constant:


pV=const.

where p is the pressure and V the volume.

In our case, this law can also be rewritten as


p_1 V_1 = p_2 V_2

where the labels 1 and 2 refer to the initial and final conditions of the gas.

For the gas in the problem, the pressure of the gas is tripled, so


p_2 = 3p_1

And re-arranging the equation we find what happens to the volume:


V_2 = (p_1 V_1)/(p_2)=(p_1 V_1)/(3p_1)=(V_1)/(3)

so, the volume is reduced to 1/3 of its original value.

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User Thordarson
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