asked 211k views
3 votes
The table shows the height of a ball that was dropped from a 380-foot tower. What was the ball's rate of fall during the first 3 seconds?

0s-380ft

1-s-350ft

2s-290ft

3s-200ft

asked
User Gisette
by
8.6k points

2 Answers

2 votes

Answer:

The correct answer is 60 feet / second.

Explanation:

We are given the height of a ball which is falling from a height of 280 feet for 3 seconds.

We are to find the ball's rate of fall during the first 3 seconds.

For that, we will take the difference between the heights and divide it by the time.

Ball's rate =
\frac { 3 8 0 - 2 0 0 } { 3 } = 60 feet / second

answered
User Svkvvenky
by
8.3k points
4 votes

Answer:

60ft/s

Explanation:

To find the rate

rate = f(3) - f(0)

-------------

3-0

rate = 200-380

---------------

3-0

rate = -180/3 = -60 ft/s

The negative tells us it is falling

The fall falls 60ft/s

answered
User Matt Haberland
by
7.8k points
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