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What are the zeros of the function f(x)=x2+12x+38

What are the zeros of the function f(x)=x2+12x+38
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What are the zeros of the function f(x)=x2+12x+38

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User Randy Swanson
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1 Answer

3 votes

Answer:

The zero would be -2.714 (x-intercept)

answered
User Veelen
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