Question

A volume of 10.0L of gas at a temperature of 5c is cooled to a temperature of 85C at constant pressure what is the new volume of gas

Answer 1

I don't know how 5°C cooled to 85°C but the answer would be 12.878L

Answer 2

At constant pressure the new volume of gas is 12.878 L.

Step-by-step explanation:

Charles's Law consists of the relationship between the volume and temperature of a certain amount of ideal gas, which is maintained at a constant pressure, by means of a proportionality constant that is applied directly. So the ratio between volume and temperature will always have the same value:

`(V)/(T) =k`

where the temperature is expressed in degrees kelvin (° K)

Then, when considering the two situations 1 and 2, keeping the amount of gas and the temperature constant, the relationship must be met:

`(V1)/(T1) =(V2)/(T2)`

In this case, you know:

• V1= 10 L
• T1= 5 +273 = 278°K (where 0°C=273°K)
• V2= ?
• T2= 85 + 273 = 358°K

Replacing:

`(10)/(278) =(V2)/(358)`

Solving:

`V2=(10)/(278) *358`

V2=12.878 L

At constant pressure the new volume of gas is 12.878 L.