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Determine the eccentricity, the type of conic, and the directrix for r=6/1+2cos theta.

Determine the eccentricity, the type of conic, and the directrix for r=6/1+2cos theta-example-1

2 Answers

3 votes

Answer:

the answer is C

Explanation:

just took the test

answered
User Lance Lefebure
by
7.5k points
5 votes

Answer:

Option c

Explanation:

The general polar form of the conic with cosine in the denominator is:


r=(ep)/(1+ecos(\theta))

Comparing the given equation (Denominator) with the general equation, we can write:

e = 2

This means eccentricity = 2. Since eccentricity is greater than 1, the given conic is a hyperbola.

The equation of directrix is x = p

Comparing the numerators of general and given equation, we can write:

ep = 6

Using the value of e, we get p = 3

Therefore, equation of directrix is x =3

Hence option c is the correct answer.

answered
User Jackie James
by
8.3k points
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