Question

What is the equation of a line passing through (-3,7) and having a slip of -1/5

A.y=-5x+22
B.y=5x+33
C.y=1/5x+32/5
D.y=-1/5x+32/5
E.y=-1/5x+22

Answer 1

`\large\boxed{D.\ y=-(1)/(5)x+(32)/(5)}`

Explanation:

The slope-intercept form of an equation of a line:

`y=mx+b`

m - slope

b - y-intercept

We have the slope m = -1/5. Substitute:

`y=-(1)/(5)x+b`

Put the coordinates of the given point (-3, 7) to the equation:

`7=-(1)/(5)(-3)+b`

`7=(3)/(5)+b` subtract 3/5 from both sides

`6(2)/(5)=b\to b=(6\cdot5+2)/(5)=(32)/(5)`