Question

Use the x-intercept method to find all real solutions of the equation.
x^3-12x^2+39x-28=0

Answer 1

d.
`x=1,4,\:or\:7`

Explanation:

The given equation is

`x^3-12x^2+39x-28=0`

To find all real solutions using the x-intercept method, we to graph the corresponding function using a graphing tool.

The corresponding function is;

`f(x)=x^3-12x^2+39x-28`

The real solutions to
`x^3-12x^2+39x-28=0`, are the x-intercepts of the graph of the corresponding function.

From the graph the x-intercepts are

(1,0),(4,0) and (7,0).

Therefore the real solutions are

`x=1,4,\:or\:7`