Question

Find the equation of the circle in standard form for the given center (h, k) and radius r: (h, k) = (0, 0), r = 4

Answer 1

`x^2+y^2=16`

Explanation:

The equation of a circle with center (h,k) and radius r is given by the formula;

`(x-h)^2+(y-k)^2=r^2`

Given (h,k)=(0,0) and r=4, we substitute the values to obtain;

`(x-0)^2+(y-0)^2=4^2`

The required equation is

`x^2+y^2=16`